If it is a theorem, is there a proof for it (02.06 mc) the figure below shows rectangle abcd with diagonals ac and db Congruent has been defined as an equivalence relation
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A relation that fulfills reflexivity, symmetry, and transitivity.
4 why use cpctc (corresponding parts of congruent triangles are congruent) instead of just definition of congruent figures especially since definitions are biconditional
use the cpctc theorem to prove that the diagonals ?bar (bd) and ?bar (ac) are perpendicular by finding the m?d in ????dec.14 yoint70°125°55°35° in the diagram of the rhombus abcd, m c = 1 1 0 ° use the cpctc theorem to prove that the diagonals b a r (b d) and b a r (a c) are perpendicular by finding the m d in d e c Ac ― ≅ bd ― cpctc identify the missing reason in the proof A sss criterion b aas theorem c sas criterion d asa criterion here’s the best way to solve it. The figure below shows a rectangle abcd having diagonals ac and db
Jimmy wrote the following proof to show that the diagonals of rectangle abcd are congruen jimmy's proof statement 1 In triangle adc and bcd, ad bc (opposite sides of a rectangle are congrue statement 2 Angle adc = angle bcd (angles of a rectangle are 907 statement 3. Math geometry geometry questions and answers given aabc and adec with congruent parts as marked, what else is needed to show congruence
C d complete the sentences below
Ii ab de then there is congruence by (1) alteratively to use (2) other of the conditions bc a (3) or ac (4) is noodod (3) (4 (1) o asa aas o cpctc (2) o asa o aas cpctc Ad be obd ab оас ec de ae o cd ceo ad obc ове o. Therefore ∠b is a right angle and abc is a ab is congruent to de because segment de was constructed so that de =ab.bc is congruent to ef because segment ef was constructed so that ef =bc. Math geometry geometry questions and answers ( 5 pts) you should have used triangle congruences in the proof for #8
now, redothat problem, but finish it off completely differently, by changing the cpctc partafter your triangle congruences and continuing on from that.
