Physicists prefer to use hermitian operators, while mathematicians are not biased towards hermitian operators Assuming that they look for the treasure in pairs that are randomly chosen from the 80 What is the fundamental group of the special orthogonal group $so (n)$, $n>2$
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I have known the data of $\\pi_m(so(n))$ from this table The generators of so(n) s o (n) are pure imaginary antisymmetric n×n n × n matrices How can this fact be used to show that the dimension of so(n) s o (n) is n(n−1) 2 n (n 1) 2 I know that an antisymmetric matrix has n(n−1) 2 n (n 1) 2 degrees of freedom, but i can't take this idea any further in the demonstration of the proof
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I have a potentially simple question here, about the tangent space of the lie group so (n), the group of orthogonal $n\times n$ real matrices (i'm sure this can be. Each of 20 families selected to take part in a treasure hunt consist of a mother, father, son, and daughter
