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The (*) means build the sensitivity list for me I doubt it matters, but i thought i would mention it just in case.

For example, if you had a statement a = b + c The functions are written in f# Then you'd want a to change every time either b or c changes

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In other words, a is sensitive to b & c

So to set this up

Always @( b or c ) begin a = b + c End but imagine you had a large always block that was sensitive to loads of signals Writing the sensitivity list would take ages The always @(*) block is sensitive to change of the values all the variables, that is read by always block or we can say which are at the right side inside the always block

In your example, there are no any variables used inside always block, so this always @(*) block will not work here As per sv lrm, always_comb is sensitive to changes within the contents of a function, whereas always @* is. The always @(*) syntax was added to the ieee verilog std in 2001 All modern verilog tools (simulators, synthesis, etc.) support this syntax

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An incomplete event_expression list of an event control is a common source of bugs in register transfer level (rtl) simulations

The implicit event_expression, @*, is a convenient shorthand that eliminates these. I am totally confused among these 4 terms Always_ff, always_comb, always_latch and always How and for what purpose can these be used?

The always construct can be used at the module level to create a procedural block that is always triggered Typically it is followed by an event control, e.g., you might write, within a module, something like Always @(posedge clk) <do stuff> always @(en or d) <do stuff> always @* <do stuff>, can also use @(*) this is the typical way to write latches, flops, etc Using images tagged :latest imagepullpolicy

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Always is specified this is great if you want to always pull

But what if you want to do it on demand Should we change our coding as suggested below Is there a difference between.done() & success:,.fail() & error I was putting together a jquery.ajax call, which i have done successfully in the past too

Imagine assign as wires and always blocks as registers (for now) , as their behavior is same. I'm stumped in excel (version 16.0, office 365) I have some cells that are formatted as number, all with values > 0, but when i use the standard sum () on them, it always shows a result of 0.0 inst.

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