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Mejor creador/a fanci ofrece videos de premium 6.3072 g >>molarity = moles of solute/volume of solution (in litres) 0.45 m = n/0.4 l n = 0.45 m × 0.4 l = 0.18 mol you need 0.18 mol of nh_4oh molar mass of nh_4oh is 35.04 g/mol mass of solute = 0.18 cancelmol × 35.04 g/cancelmol = 6.3072 g So this is a propanol derivative Both names seem to be unambiguous.
The thing to keep in mind here is that nitric acid is a strong acid, which means that it will ionize completely in aqueous solution to produce hydronium cations, h3o+, and nitrate anions, no− 3 Hno3(aq) +h2o(l) → h3o+ (aq) + no− 3(aq) notice that every mole of nitric acid that is dissolved in water produces 1 mole of hydronium cations This means that the concentration of hydronium. Because n aoh → n a+ + oh − and n i2+ + 2oh −→n i(oh)2 total mols of n aoh
60ml ⋅ 0.45m ol/l = 27mm ol of n aoh (dont forget the m for milli=one thousandth) this will produce 27 2 = 13.5mm ol of n i(oh)2 now you multiply this by the molecular mass number to get the weight in milligrams (divide by 1000 to get the grams)
Nickel (ii)hydroxide may be formed without or (more likely. No, the oh group in phenol is by definition at c1 > the structure of phenol is you can draw the structure like this It is phenol because the ring carbon attached to the oh group is now c1
The oh carbon can be on any carbon atom of the ring, and the compound is still phenol, This is also a 1:1 ratio. If 575 grams of frozen ethonal are warmed to the freezing point of ethanol, how much heat is required to melt all of this frozen ethanol, ch3ch2oh, at the freezing point The molar heat of vaporization of ethanol= 4.95 kj/mol
Since water is in excess, 67.7 g mgo are needed to produce 98.0 g mg(oh)_2
Balanced equation mgo(s) + h_2o(l)rarrmg(oh)_2(s) moles magnesium hydroxide start with the given mass of mg(oh)_2 and convert it to moles by dividing by its molar mass (58.319 g/mol) Since molar mass is a fraction, g/mol, we can divide by multiplying by the reciprocal of the molar mass, mol/g.
