Physicists prefer to use hermitian operators, while mathematicians are not biased towards hermitian operators Instead, you can save this post to reference later. What is the fundamental group of the special orthogonal group $so (n)$, $n>2$
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The generators of so(n) s o (n) are pure imaginary antisymmetric n×n n × n matrices How can this fact be used to show that the dimension of so(n) s o (n) is n(n−1) 2 n (n 1) 2 I know that an antisymmetric matrix has n(n−1) 2 n (n 1) 2 degrees of freedom, but i can't take this idea any further in the demonstration of the proof I have known the data of $\\pi_m(so(n))$ from this table
I have a potentially simple question here, about the tangent space of the lie group so (n), the group of orthogonal $n\times n$ real matrices (i'm sure this can be. I've found lots of different proofs that so(n) is path connected, but i'm trying to understand one i found on stillwell's book naive lie theory It's fairly informal and talks about paths in a very You'll need to complete a few actions and gain 15 reputation points before being able to upvote
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