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6.3072 g >>molarity = moles of solute/volume of solution (in litres) 0.45 m = n/0.4 l n = 0.45 m × 0.4 l = 0.18 mol you need 0.18 mol of nh_4oh molar mass of nh_4oh is 35.04 g/mol mass of solute = 0.18 cancelmol × 35.04 g/cancelmol = 6.3072 g Calculate moles of acid, calculate moles of base

So this is a propanol derivative Co₃²⁻ + h₂o ⇌ hco₃⁻ + oh⁻ hco₃⁻ + h₂o ⇌ h₂co₃ + oh⁻ b. Both names seem to be unambiguous.

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If naoh is added, then we have increased the concentration of hydroxide ions

> (a) with hcn the hcn adds across the α c=o group to form a cyanohydrin

Underbrace (ch_3cocooh)_color (red) (pyruvic acid) + hcn →. Each water molecule contains two hydrogens, so we multiply water by two to get The sodium ions remain in solution as spectator ions If xs sodium hydroxide is added the precipitate redissolves to give the soluble plumbate (ii) ion

A simple way of writing this is The correct answer is a) hydroxide, carbonate, and hydrogen carbonate Alkalinity is another word for basicity (the concentration of hydroxide ions) A) hydroxide ions oh⁻ are the strongest base you can have in water